The graph of y=(x3)^2(x4)^3 represents a graph of a polynomial function On the given graph you can find all of the important points for function y=(x3)^2(x4)^3 (if they exist)Which statement about the relationship between these two graphs is true? Graph #y2=2/3(x4)# The easiest way to find points on the line is to convert the given equation in point slope form to slope intercept form #y=mxb#, where #m# is the slope, and #b# is the yintercept In order to do this, solve the point slope equation for #y# #y2=2/3(x4)# Add #2# to both sides #y=2/3(x4)2# Simplify #2/3(x4)# to #(2(x4))/3#
Answered Identify The Function Shown In This Bartleby
Graph the circle (x+3)^2+(y-4)^2=4
Graph the circle (x+3)^2+(y-4)^2=4-4 units to the left Which equation has a graph that is a parabola with a vertex at (5, 3)?Find the equation of the parabolic graph that passes through the points {eq}( x, y) = (1,0), (2, 3), (4, 3) {/eq} Exhibit the three linear equations in the three
17 Transformations 123 2 to all of the xvalues of the points on the graph of y= f(x) to e ect a shift to the right 2 units Generalizing these notions produces the following resultIn analytic geometry, an asymptote (/ ˈ æ s ɪ m p t oʊ t /) of a curve is a line such that the distance between the curve and the line approaches zero as one or both of the x or y coordinates tends to infinityIn projective geometry and related contexts, an asymptote of a curve is a line which is tangent to the curve at a point at infinity The word asymptote is derived from the GreekY = (x 5)2 3 Which equation has a graph that is a parabola with a vertex at (1, 1)?
Think about it as adding a value to x before you take the square root—so the y value gets moved to a different x value For example, for , the square root is 3 if x = 9 For, the square root is 3 when x 1 is 9, so x is 8 Changing x to x 1 shifts the graph to the left by 1 unit (from 9 to 8) Changing x to x − 2 shifts the graph to theThe graph of a new line is formed by changing the slope of the original line to 2 / 3 and the yintercept to 4 Which statement about the relationship between these two graphs is true? This is one of the several ways to graph a line From the given y=(3x)/24,Set x=0 then y=4 y=4 when x=0 a point is located at (0, 4) next, set y=0, then solve for x that is 0=(3x)/24 so that x=8/3 x=8/3 when y=0 another point is located at (8/3, 0) plot the two points graph{y=(3x)/24 10, 10, 6, 6} Have a nice day!
4x 3 a) Write down the coordinates of the turning point on the graph of y = x2 4x 3 (1) b) Use the graph to find the roots of the equation y = x2 4x 3 (2) please i'm doin eeduanswerscomAlso, if there is more than one exponential term in the function, the graph may look differentThe following are a couple of examples, just to show you how they work Graph y = 3×2 –x2 Because the power is a negative quadratic, the power is always negative (or zero) Then this graph should generally be pretty close to the x axisThe graph of 2 2 2 2 3 4 4 x x y x x has horizontal asymptote at 12y but no The graph of 2 2 2 2 3 4 4 x x y x x has aa School Lake Braddock Secondary;
2x2y=4 Geometric figure Straight Line Slope = 1 xintercept = 2/1 = 0000 yintercept = 2/1 = 0000 Rearrange Rearrange the equation by subtracting what is to the right of the 3x2y=4 3x−2y = 4 http//wwwtigeralgebracom/drill/3x2y=4/Get an answer for '`y = 3/2 x^(2/3) 4 , 1, 27` Find the arc length of the graph of the function over the indicated interval' and find homework help for other Math questions at eNotes1 Graph y x= −2 3 4 and describe the equation as a transformation of the parent graph (8 pts) x y 2 Graph y x=− 2 5 6 and describe the equation as a transformation of the parent graph(8 pts) x y 3 Describe the resulting equation if the parent graph y x= 2is scaled by vertically by 2 units, shifted 3 units right, and shifted
I want to graph the curve of y=(4x^2)^5 without using a graphing calculator To do this, I'm suppose to find domain, y and x intercepts, asymptotes, intervals of increase/decrease, local max/min, concavity and points of inflection I got all the way to the step where I'm solving the concavity and I'm stuckGraph the given equation First plot the solutions of the equation for the given values of {eq}x {/eq}, and then connect the points with a smooth graphExample 4 Graph x y Solution First graph x = y Next check a point not on the line Notice that the graph of the line contains the point (0,0), so we cannot use it as a checkpoint To determine which halfplane is the solution set use any point that is obviously not on the line x = y The point (
Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more Ex 43, 1 Draw the graph of each of the following linear equations in two variables x y = 4 x y = 4 To draw the graph, we need at least two solutions of the equation Plotting points Ex 43, 1 Draw the graph of each of the following linear equations in two variYou can graph this by using the slope intercepts and the y intercept The slope of this equation is the constant beside the "x", which is math4/1, and the formula for slope is rise/run and the yintercept(where the line intersects the yaxis) i
Section 95 Graphing Other Trigonometric Functions 499 Each graph below shows fi ve key xvalues that you can use to sketch the graphs of y = a tan bx and y = a cot bx for a > 0 and b > 0 These are the xintercept, the xvalues where the asymptotes occur, and the xvalues halfway between the xintercept and the asymptotes At each halfway point, the value of the function is4 units to the left 4 units to the right 8 units to the left 8 units to the right 4 units to the left Which equation has a graph that is a parabola with a vertex at (2, 0)?This becomes y= (3/4)x452 or y= (3/4)x65 The point (6, 2) should work
Which phrase best describes the translation from the graph y = 2(x 15)2 3 to the graph of y = 2(x 11)2 3?Which phrase best describes the translation from the graph y = 2(x 15)2 3 to the graph of y = 2(x 11)2 3?This is in the form of y=mxb, where m is the slope, and b is the yintercept So on an x y graph, and preferably on graph paper, mark one point on the y intercept, in this case y=3 Now you'll use the slope, 4 Since 4 is positive, and 1st degree, this graph will be a line rising from left to right
About Graphing Quadratic Functions Quadratic function has the form $ f(x) = ax^2 bx c $ where a, b and c are numbers You can sketch quadratic function in 4 steps I will explain these steps in following examplesRegents Exam Questions GGPEA1 Equations of Circles 4a Name _____ wwwjmaporg 4 13 The diagram below is a graph of circle O Which equation represents circle O?The graph of y = f (x) is horizontally stretched about the yaxis by a factor of 1 _ 2 and then vertically stretched about the xaxis by a factor of 3 Apply the horizontal stretch by a • —2 y x 2 4 6 8 1 2 3 0 y = f (x) y = f (2 x) (0, 0) (1, 1) (4, 2) (45, 3) (2, 2) (05, 1) (9, 3) factor of 1 _ 2 to obtain the graph of y = f (2 x)
showing how to graph a simple quadratic with 5 points(2/5)() – 4 = 8 – 4 = 4 Even if I skip a few of the points at the ends (which I think I will), this is gonna be a wide graph, at least in terms of the scale By the way, there are other methods for graphing straight lines, such as graphing from the intercepts or graphing from the yThen graph the equation by hand Use a graphing calculator to verify your worky = (x 3) Write an equivalent expression for the function that could be graphed with a graphing calculator Then graph the function with a graphing calculatorf (x) = log4 (x
Y=3/4(4)2 y=32 y=5 so the other point is (4,5) Put a dot on the yaxis (the axis that goes up and down) at (0,2) For the point (4,5) start at the origin (the place where the x and y axis cross), go right 4, then up 5 and put a second point Connect the two points with a line, and your graph should look like this Happy Calculating!!!Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyType Notes Uploaded By mfantaye08 Pages 18 This preview shows page 11 14 out of 18 pages
To plot the graph of a function, you need to take the following steps − Define x, by specifying the range of values for the variable x, for which the function is to be plotted Define the function, y = f (x) Call the plot command, as plot (x, y) Following example would demonstrate the concept Let us plot the simple function y = x for theRecall that a function must have the property that no two different ordered pairs have the same first coordinate That is, each value of x must have a separate unique value of y Look at the graph of y = x^2 in Example 4 Each x value has a unique y value Look at the graph of x = y^2 2 in Example 5 At x = 3 there are two y values, 1 and 1 👍 Correct answer to the question Here is the graph of yox?
1) (x −5)2 (y 3)2 =42) (x 5)2 (y −3)2 =43) (x −5)2 (y 3)2 =164) (x 5)2 (y −3)2 =1614 Which equation represents circle O shown in the graph below?The graph of a function is contained in a Cartesian product of sets An X–Y plane is a cartesian product of two lines, called X and Y, while a cylinder is a cartesian product of a line and a circle, whose height, radius, and angle assign precise locations of the points Fibre bundles are not Cartesian products, but appear to be up close hello y 2 = 3/4 (x4) y = (3/4)x 5 x=0 y = 5 x=4 y = 8 two points (0,5) ( 4 , 8) look graph search rotate tramwayniceix and 67 more users found this answer helpful
Y will equal 2/3 x Pick several values for x Multiply each value of x by 2/3 (for example, if x= 2 then y will be 2/3 times 2 or 4/3) Once you have done this for all of your x values, you are ready to graph Locate your first x value on the horizontal axis and go up to the y value you calculated and make a small dotCourse Title MATH AP Calculu;Answers archive Answers Click here to see ALL problems on Linearequations Question graph y 2= 3/4 (x 6) using the point slope given in the equation Answer by Boreal () ( Show Source ) You can put this solution on YOUR website!
Graph y=2/3x4 y = 2 3 x − 4 y = 2 3 x 4 Rewrite in slopeintercept form Tap for more steps The slopeintercept form is y = m x b y = m x b, where m m is the slope and b b is the yintercept y = m x b y = m x b Reorder terms y = 2 3 x − 4 y = 2 3 x 4 y = 2 3x− 4 y = 2 3 x 4You can clickanddrag to move the graph around If you just clickandrelease (without moving), then the spot you clicked on will be the new center To reset the zoom to the original click on the Reset button Using "a" Values There is a slider with "a =" on it You can use "a" in your formula and then use the slider to change the value of "a Solve the equation for y;
PreAlgebra Graph y (2)=3/4* (x1) y − (−2) = − 3 4 ⋅ (x 1) y ( 2) = 3 4 ⋅ ( x 1) Move all terms not containing y y to the right side of the equation Tap for more steps Subtract 2 2 from both sides of the equation y = − 3 x 4 − 3 4 − 2 y = 3 x 4 3 4 2This is a very quick review of how to graph y =_2f(x__3)__4 given the graph of y = f(x) by table For more information, go to bitly/graph_transfThe graphs of f and g have the same x intercepts The graph of f has a maximum point and the graph of g has a minimum point The graphs are equivalent s Question 18 SURVEY 30 seconds Q A graph of f (x) = 6x 2 11x 3 is shown on the grid
Get an answer for 'Find the total length of the graph of the astroid `x^(2/3) y^(2/3) = 4`' and find homework help for other Math questions at eNotesWe designate (3, 5) as (x 2, y 2) and (4, 2) as (x 1, y 1) Substituting into Equation (1) yields Note that we get the same result if we subsitute 4 and 2 for x 2 and y 2 and 3 and 5 for x 1 and y 1 Lines with various slopes are shown in Figure 78 belowThe graph of the equation x^2/3 y^2/3 = 4^2/3 is one of a family of curves called astroids because of their star like appearance (as shown in the accompanying figure) Find the length of this particular astroid by finding the length of half the firstquadrant portion, y = (4^2/3 x^2/3)^3/2, Squareroot 2 lessthanorequalto x lessthanorequalto 4, and multiplying by 8
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